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3x(3.14^2/4)=0.053
We move all terms to the left:
3x(3.14^2/4)-(0.053)=0
We add all the numbers together, and all the variables
3x(3.14^2/4)-0.053=0
We multiply parentheses
9x^2-0.053=0
a = 9; b = 0; c = -0.053;
Δ = b2-4ac
Δ = 02-4·9·(-0.053)
Δ = 1.908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.908}}{2*9}=\frac{0-\sqrt{1.908}}{18} =-\frac{\sqrt{}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.908}}{2*9}=\frac{0+\sqrt{1.908}}{18} =\frac{\sqrt{}}{18} $
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